206. Reverse Linked List
Question
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Given the head of a singly linked list, reverse the list, and return the reversed list .
Example 1:
Input: head = [1,2,3,4,5] Output: [5,4,3,2,1]
Example 2:
Input: head = [1,2] Output: [2,1]
Example 3:
Input: head = [] Output: []
Constraints:
- The number of nodes in the list is the range
[0, 5000]. -5000 <= Node.val <= 5000
Follow up: A linked list can be reversed either iteratively or recursively. Could you implement both?
Solutions
ListNode* reverseList(ListNode* head) {
ListNode* prev = nullptr;
ListNode* curr = head;
while (curr) {
ListNode* next = curr->next;
curr->next = prev;
prev = curr;
curr =next;
}
return prev;
}