56. Merge Intervals
Solutions
vector<vector<int>> merge(vector<vector<int>> &intervals){
sort(intervals.begin(), intervals.end(), [](const vector<int>& a, const vector<int>& b) {
return a[0] < b[0];
});
vector<vector<int>> result;
for (const auto& interval : intervals) {
if (result.empty() || result.back()[1] < interval[0]) {
result.push_back(interval);
} else {
result.back()[1] = max(result.back()[1], interval[1]);
}
}
return result;
}
Time Complexity:
Space Complexity: